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U.S. Route 4

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(Redirected from U.S. Route 4 in New York)
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Route information
Length249.84 mi[1] (402.08 km)
Existed1926[1]–present
Major junctions
West endFile:US 9.svgFile:US 20.svg US 9 / US 20 near Albany, NY
Major intersectionsFile:I-90.svg I-90 near Albany, NY
File:US 7.svg US 7 in Rutland, VT
File:I-89.svgFile:I-91.svgFile:US 5.svg I-89 / I-91 / US 5 in White River Junction, VT
File:I-89.svg I-89 in Lebanon, NH
File:I-93.svgFile:US 3 square.svgFile:US 202 square.svg I-93 / US 3 / US 202 in Concord, NH
East endFile:I-95.svgFile:US 1 Bypass.svgFile:NH Route 16.svg I-95 / US 1 Byp. / NH 16 in Portsmouth, NH
Location
CountryUnited States
Highway system

U.S. Route 4 is a highway in the United States. It travels from East Greenbush, New York, near Albany to Portsmouth, New Hampshire. It passes through the state of Vermont. It has a total length of 250 miles. Before being a US highway, Route 4 was part of several New England highways.

References[change]

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